12=3x(3x+2)-9x^2+12

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Solution for 12=3x(3x+2)-9x^2+12 equation: 



12=3x(3x+2)-9x^2+12

We move all terms to the left:

12-(3x(3x+2)-9x^2+12)=0



We calculate terms in parentheses: -(3x(3x+2)-9x^2+12), so:

3x(3x+2)-9x^2+12

determiningTheFunctionDomain
-9x^2+3x(3x+2)+12

We multiply parentheses

-9x^2+9x^2+6x+12

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

-6x-12+12=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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